Soalan 1:
Permudahkan setiap yang berikut.
$$
\text { (a) } 3^2 \times 3 \times 3^4
$$
Permudahkan setiap yang berikut.
$$
\text { (a) } 3^2 \times 3 \times 3^4
$$
$$
\text { (b) }(-0.4)^4 \times(-0.4)^3 \times(-0.4)
$$
$$
\text { (c) }\left(\frac{4}{7}\right) \times\left(\frac{4}{7}\right)^3 \times\left(\frac{4}{7}\right)^5
$$
$$
\text { (d) }\left(-1 \frac{2}{5}\right)^2 \times\left(-1 \frac{2}{5}\right)^3 \times\left(-1 \frac{2}{5}\right)^5
$$
$$
\text { (e) } 4 m^2 \times \frac{1}{2} m^3 \times(-3) m^4
$$
$$
\text { (f) } n^6 \times \frac{4}{25} n^2 \times \frac{5}{4} n^3 \times n
$$
$$
\text { (g) }-x^4 \times \frac{25}{4} x \times \frac{12}{5} x^2
$$
$$
\text { (h) }-\frac{1}{2} y^5 \times(-6) y^3 \times \frac{1}{3} y^4
$$
Penyelesaian:
(a)
$$
\begin{aligned}
& 3^2 \times 3 \times 3^4 \\
& =3^{2+1+4} \\
& =3^7
\end{aligned}
$$
(b)
$$
\begin{aligned}
& (-0.4)^4 \times(-0.4)^3 \times(-0.4) \\
& =(-0.4)^{4+3+1} \\
& =(-0.4)^8
\end{aligned}
$$
(c)
$$
\begin{aligned}
& \left(\frac{4}{7}\right) \times\left(\frac{4}{7}\right)^3 \times\left(\frac{4}{7}\right)^5 \\
& =\left(\frac{4}{7}\right)^{1+3+5} \\
& =\left(\frac{4}{7}\right)^9
\end{aligned}
$$
(d)
$$
\begin{aligned}
& \left(-1 \frac{2}{5}\right)^2 \times\left(-1 \frac{2}{5}\right)^3 \times\left(-1 \frac{2}{5}\right)^5 \\
& =\left(-1 \frac{2}{5}\right)^{2+3+5} \\
& =\left(-1 \frac{2}{5}\right)^{10}
\end{aligned}
$$
(e)
$$
\begin{aligned}
& 4 m^2 \times \frac{1}{2} m^3 \times(-3) m^4 \\
= & {\left[4 \times \frac{1}{2} \times(-3)\right]\left(m^2 \times m^3 \times m^4\right) } \\
= & -6 m^{2+3+4} \\
= & -6 m^9
\end{aligned}
$$
(f)
$$
\begin{aligned}
& n^6 \times \frac{4}{25} n^2 \times \frac{5}{4} n^3 \times n \\
& =\left(\frac{4}{25} \times \frac{5}{4}\right)\left(n^6 \times n^2 \times n^3 \times n^1\right) \\
& =\left(\frac{1}{5}\right) n^{6+2+3+1} \\
& =\frac{n^{12}}{5}
\end{aligned}
$$
(g)
$$
\begin{aligned}
& -x^4 \times \frac{25}{4} x \times \frac{12}{5} x^2 \\
& =\left(-1 \times \frac{25}{4} \times \frac{12}{5}\right)\left(x^4 \times x \times x^2\right) \\
& =(-15) x^{4+1+2} \\
& =-15 x^7
\end{aligned}
$$
(h)
$$
\begin{aligned}
& -\frac{1}{2} y^5 \times(-6) y^3 \times \frac{1}{3} y^4 \\
& =\left(-\frac{1}{2} \times-6 \times \frac{1}{3}\right)\left(y^5 \times y^3 \times y^4\right) \\
& =y^{5+3+4} \\
& =y^{12}
\end{aligned}
$$
\text { (b) }(-0.4)^4 \times(-0.4)^3 \times(-0.4)
$$
$$
\text { (c) }\left(\frac{4}{7}\right) \times\left(\frac{4}{7}\right)^3 \times\left(\frac{4}{7}\right)^5
$$
$$
\text { (d) }\left(-1 \frac{2}{5}\right)^2 \times\left(-1 \frac{2}{5}\right)^3 \times\left(-1 \frac{2}{5}\right)^5
$$
$$
\text { (e) } 4 m^2 \times \frac{1}{2} m^3 \times(-3) m^4
$$
$$
\text { (f) } n^6 \times \frac{4}{25} n^2 \times \frac{5}{4} n^3 \times n
$$
$$
\text { (g) }-x^4 \times \frac{25}{4} x \times \frac{12}{5} x^2
$$
$$
\text { (h) }-\frac{1}{2} y^5 \times(-6) y^3 \times \frac{1}{3} y^4
$$
Penyelesaian:
(a)
$$
\begin{aligned}
& 3^2 \times 3 \times 3^4 \\
& =3^{2+1+4} \\
& =3^7
\end{aligned}
$$
(b)
$$
\begin{aligned}
& (-0.4)^4 \times(-0.4)^3 \times(-0.4) \\
& =(-0.4)^{4+3+1} \\
& =(-0.4)^8
\end{aligned}
$$
(c)
$$
\begin{aligned}
& \left(\frac{4}{7}\right) \times\left(\frac{4}{7}\right)^3 \times\left(\frac{4}{7}\right)^5 \\
& =\left(\frac{4}{7}\right)^{1+3+5} \\
& =\left(\frac{4}{7}\right)^9
\end{aligned}
$$
(d)
$$
\begin{aligned}
& \left(-1 \frac{2}{5}\right)^2 \times\left(-1 \frac{2}{5}\right)^3 \times\left(-1 \frac{2}{5}\right)^5 \\
& =\left(-1 \frac{2}{5}\right)^{2+3+5} \\
& =\left(-1 \frac{2}{5}\right)^{10}
\end{aligned}
$$
(e)
$$
\begin{aligned}
& 4 m^2 \times \frac{1}{2} m^3 \times(-3) m^4 \\
= & {\left[4 \times \frac{1}{2} \times(-3)\right]\left(m^2 \times m^3 \times m^4\right) } \\
= & -6 m^{2+3+4} \\
= & -6 m^9
\end{aligned}
$$
(f)
$$
\begin{aligned}
& n^6 \times \frac{4}{25} n^2 \times \frac{5}{4} n^3 \times n \\
& =\left(\frac{4}{25} \times \frac{5}{4}\right)\left(n^6 \times n^2 \times n^3 \times n^1\right) \\
& =\left(\frac{1}{5}\right) n^{6+2+3+1} \\
& =\frac{n^{12}}{5}
\end{aligned}
$$
(g)
$$
\begin{aligned}
& -x^4 \times \frac{25}{4} x \times \frac{12}{5} x^2 \\
& =\left(-1 \times \frac{25}{4} \times \frac{12}{5}\right)\left(x^4 \times x \times x^2\right) \\
& =(-15) x^{4+1+2} \\
& =-15 x^7
\end{aligned}
$$
(h)
$$
\begin{aligned}
& -\frac{1}{2} y^5 \times(-6) y^3 \times \frac{1}{3} y^4 \\
& =\left(-\frac{1}{2} \times-6 \times \frac{1}{3}\right)\left(y^5 \times y^3 \times y^4\right) \\
& =y^{5+3+4} \\
& =y^{12}
\end{aligned}
$$