Soalan 14:
Diberi k3=9−32×6412, cari nilai bagi k.
Penyelesaian:
k3=9−32×6412 =(32)−32×(26)12 =3−3×23 =(23)3k=23
Diberi k3=9−32×6412, cari nilai bagi k.
Penyelesaian:
k3=9−32×6412 =(32)−32×(26)12 =3−3×23 =(23)3k=23
Soalan 15:
Diberi 9x+2÷34=3x+1, hitung nilai bagi x.
Penyelesaian:
9x+2÷34=3x+1(32)x+2÷34=3x+1 32x+4÷34=3x+1 2x+4−4=x+1 2x=x+1 x=1
Diberi 9x+2÷34=3x+1, hitung nilai bagi x.
Penyelesaian:
9x+2÷34=3x+1(32)x+2÷34=3x+1 32x+4÷34=3x+1 2x+4−4=x+1 2x=x+1 x=1
Soalan 16:
Permudahkan: (−2x5y−2z16)3÷1√x2z
Penyelesaian:
(−2x5y−2z16)3÷1√x2z=−8x15y−6z12×√x2z=−8x15y−6z12×(x2z)12=−8x15y−6z12×xz12=−8x15+1y−6=−8x16y6
Permudahkan: (−2x5y−2z16)3÷1√x2z
Penyelesaian:
(−2x5y−2z16)3÷1√x2z=−8x15y−6z12×√x2z=−8x15y−6z12×(x2z)12=−8x15y−6z12×xz12=−8x15+1y−6=−8x16y6
Soalan 17:
Cari nilai bagi setiap yang berikut.
(a) (23)2 × 24 ÷ 25
(b)
a2×a12(a23×a13)−2
Penyelesaian:
(a)
(23)2 × 24 ÷ 25= 26 × 24 ÷ 25
= 26+4-5
= 25
= 32
(b)
a2×a12(a23×a13)−2=a2+12(a23×a13)−2 =a2+12(a23+13)−2 =a52a−2 =a52−(−2) =a52+42 =a92