Soalan 1:
Selesaikan persamaan linear yang berikut.
(a) \(x-10=3\)
(b) \(4 x-1=7\)
(c) \(\frac{x}{6}+3=5\)
(d) \(\frac{x+8}{2}=9\)
(e) \(3(x+2)=5 x\)
(f) \(\frac{2}{3} x-4=x+1\)
Penyelesaian:
(a)
\(\begin{aligned} x-10 & =3 \\ x-10+10 & =3+10 \\ x & =13 \end{aligned}\)
(b)
(c)
\(\begin{aligned} \frac{x}{6}+3 & =5 \\ \frac{x}{6}+3-3 & =5-3 \\ \frac{x}{6} & =2 \\ \frac{x}{6} \times 6 & =2 \times 6 \\ x & =12 \\ \end{aligned}\)
(d)
\(\begin{aligned} \frac{x+8}{2} & =9 \\ \frac{x+8}{2} \times 2 & =9 \times 2 \\ x+8 & =18 \\ x+8-8 & =18-8 \\ x & =10\end{aligned}\)
(e)
\(\begin{aligned} 3(x+2) & =5 x \\ 3 x+6 & =5 x \\ 3 x+6-3 x & =5 x-3 x \\ 6 & =2 x \\ 6 \times \frac{1}{2} & =2 x \times \frac{1}{2} \\ 3 & =x \\ x & =3\end{aligned}\)
(f)
\(\begin{aligned} \frac{2}{3} x-4 & =x+1 \\ \frac{2}{3} x-4-x & =x+1-x \\ -\frac{1}{3} x-4 & =1 \\ -\frac{1}{3} x-4+4 & =1+4 \\ -\frac{1}{3} x & =5 \\ -\frac{1}{3} x \times(-3) & =5 \times(-3) \\ x & =-15\end{aligned}\)
Selesaikan persamaan linear yang berikut.
(a) \(x-10=3\)
(b) \(4 x-1=7\)
(c) \(\frac{x}{6}+3=5\)
(d) \(\frac{x+8}{2}=9\)
(e) \(3(x+2)=5 x\)
(f) \(\frac{2}{3} x-4=x+1\)
Penyelesaian:
(a)
\(\begin{aligned} x-10 & =3 \\ x-10+10 & =3+10 \\ x & =13 \end{aligned}\)
(b)
(c)
\(\begin{aligned} \frac{x}{6}+3 & =5 \\ \frac{x}{6}+3-3 & =5-3 \\ \frac{x}{6} & =2 \\ \frac{x}{6} \times 6 & =2 \times 6 \\ x & =12 \\ \end{aligned}\)
(d)
\(\begin{aligned} \frac{x+8}{2} & =9 \\ \frac{x+8}{2} \times 2 & =9 \times 2 \\ x+8 & =18 \\ x+8-8 & =18-8 \\ x & =10\end{aligned}\)
(e)
\(\begin{aligned} 3(x+2) & =5 x \\ 3 x+6 & =5 x \\ 3 x+6-3 x & =5 x-3 x \\ 6 & =2 x \\ 6 \times \frac{1}{2} & =2 x \times \frac{1}{2} \\ 3 & =x \\ x & =3\end{aligned}\)
(f)
\(\begin{aligned} \frac{2}{3} x-4 & =x+1 \\ \frac{2}{3} x-4-x & =x+1-x \\ -\frac{1}{3} x-4 & =1 \\ -\frac{1}{3} x-4+4 & =1+4 \\ -\frac{1}{3} x & =5 \\ -\frac{1}{3} x \times(-3) & =5 \times(-3) \\ x & =-15\end{aligned}\)