1.2.3 Indeks, Praktis Berformat PT3


Soalan 9:
Diberi bahawa 8× 8 p+1 =( 8 5 )( 8 3 ), cari nilai bagi p.

Penyelesaian:
8× 8 p+1 =( 8 5 )( 8 3 ) 8 1+p+1 = 8 5+3 2+p=8 p=6

Soalan 10:
Diberi bahawa  2 5 × 2 7 2 10 = 2 p , cari nilai bagi p.

Penyelesaian:
2 5 × 2 7 2 10 = 2 p 2 5+710 = 2 p 2 2 = 2 p p=2

Soalan 11:
Permudahkan:  12 p 10 q 6 3 p 4 q 2 × ( 4p q 3 ) 2

Penyelesaian:
12 p 10 q 6 3 p 4 q 2 × ( 4p q 3 ) 2 = 12 p 10 q 6 3 p 4 q 2 ×16 p 2 q 6   = 12 1 p 1042 q 626 3 1 × 16 4   = p 4 q 2 4   = p 4 4 q 2

Soalan 12:
Permudahkan:  a b 2 × ( 8 a 3 b 6 ) 1 3 ( a 2 b 4 ) 1 2

Penyelesaian:
a b 2 × ( 8 a 3 b 6 ) 1 3 ( a 2 b 4 ) 1 2 = a b 2 ×( 8 1 3 a 3 ( 1 3 ) b 6( 1 3 ) ) a 2( 1 2 ) b 4( 1 2 )    = a b 2 ×2a b 2 a b 2    =2a b 2

Soalan 13:
Selesaikan:  3 2n+1 = 3 n ×9 ( 9 1 2 ) 3

Penyelesaian:
3 2n+1 = 3 n ×9 ( 9 1 2 ) 3 3 2n+1 = 3 n × 3 2 3 3 3 2n+1 = 3 n+2( 3 ) 2n+1=n+5    n=4

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